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What volume of 2M HCl, a common laboratory stock solution, must be used to prepare 150.0 mL of 1M HCl? show work please
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What volume of 2M HCl, a common laboratory stock solution, must be used to prepare 150.0 mL of 1M HCl? show work please

User Coolprarun
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1 Answer

7 votes

Answer: 75.0 mL.

Step-by-step explanation:

  • We have a rule says that "the number of millimoles before dilution is the same after dilution".
  • This rule can be expressed as (M1V1)before dilution = (M2V2)after dilution.
  • Before dilution: M1 = 2.0 M & V1 = ??? (The volume needed to be calculated)
  • After dilution: M2 = 1.0 M & V2 = 150.0 mL.
  • Now, the volume must be used from the stock to prepare the desired solution:
  • V1 before dilution = (M2V2)after dilution / (M1) = (1.0 M x 150.0 mL) / (2.0 M) = 75.0 mL.
User Richard Barber
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