Answer:
The height of a jugglers ball that has been in the air for 1.5 seconds is 6.5 feet
Explanation:
we are given height equation as
![h=-16t^2+25t+5](https://img.qammunity.org/2020/formulas/mathematics/high-school/mcmx1dlw2cc61juwjfy93azk2jxzyn0vr7.png)
where
h is the height in feet of a Juggler's ball after t seconds
now, we can plug t=1.5
![h=-16(1.5)^2+25(1.5)+5](https://img.qammunity.org/2020/formulas/mathematics/high-school/i51erqs6wfg2qvnnpkvlq03t8rl1efnaxe.png)
we can solve for h
![h=42.5-16\cdot \:1.5^2](https://img.qammunity.org/2020/formulas/mathematics/high-school/8vksqg18bb5e9mzjx9eylv57fyx0syj776.png)
![h=42.5-36](https://img.qammunity.org/2020/formulas/mathematics/high-school/5mekgehwa9n2jxgd21q8d8vmqkxrp3dm2v.png)
![h=6.5](https://img.qammunity.org/2020/formulas/mathematics/high-school/zl8mhx9mjvupq07pc3okwnm53lfxbv71lh.png)
So,
The height of a jugglers ball that has been in the air for 1.5 seconds is 6.5 feet