1 Answer

Kyle Baran · Answer 1 · 2020-01-30T13:08:11+0000

Answer:

The height of a jugglers ball that has been in the air for 1.5 seconds is 6.5 feet

Explanation:

we are given height equation as

h=-16t^2+25t+5

where

h is the height in feet of a Juggler's ball after t seconds

now, we can plug t=1.5

h=-16(1.5)^2+25(1.5)+5

we can solve for h

$h=42.5-16\cdot \:1.5^2$

h=42.5-36

h=6.5

So,

The height of a jugglers ball that has been in the air for 1.5 seconds is 6.5 feet

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