Question

What is δg for the formation of solid uranium hexafluoride from uranium and fluorine at 25∘c when the partial pressure of f2 is 0.054 atm ? the standard free energy of formation of uf6(s) is -2068 kj/mol?

Answer 1

The reaction is

`U(s)+3F_(2) (g)-->UF_(6) (s)`

the Q of reaction will be

`Q = (1)/((pF_(2))^(3))`

`Q = (1)/((0.054)^(3)  ) = 6350.66`

Δ
`G=`Δ
`G^(0)+RTlnQ`

Putting values

ΔG = -2068000 + (8.314)(298)lnQ

ΔG = -2068000 + (8.314)(298)ln(6350.66) = -2046305 J /mol = -2046.3 kJ / mol