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A sample of atmospheric gas collected at an industrial site is stored in a 250 mL amber glass bottle that has a pressure of 1.02 atm and a temperature of 20.3°C. It was placed in an ice chest whose internal temperature is -2.0°C. What will be the new pressure of the gas sample once the gas temperature in the jar equilibrates to that of the ice chest?

User Georgio
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User Somesh
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Answer: The new pressure of the gas sample once the gas temperature in the jar 0.9424 atm.

Step-by-step explanation:

Volume of the gas = 250 mL

Pressure of the gas at
T_1=P_1

Pressure of the gas at
T_2=P_2

At the constant volume pressure of the gas is directly proportional to the temperature of the gas in Kelvins that is Gay-Lussac's Law


P_1=1.02 atm ,
T_1=20.3^oC=293.3 K


P_2=? ,
T_2=-2^oC=271 K


(P_1)/(T_1)=(P_2)/(T_2)


(P_1)/(T_1)* T_2=P_2=(1.02 atm)/(293.3 K)* 271 K=0.9424 atm

The new pressure of the gas sample once the gas temperature in the jar 0.9424 atm.

User Pattersonc
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