Answer:
see explanation
Explanation:
Given
÷
![(x^2-4x+4)/(4x+2)](https://img.qammunity.org/2020/formulas/mathematics/high-school/35gek89ffqob93yoamcoh75lw6h67zb1ro.png)
The first step is to factor numerators/denominators, if possible
x² - 4 = (x - 2)(x + 2) ← difference of squares
x² - 4x + 4 = (x - 2)(x - 2) ← perfect square
4x + 2 = 2(2x + 1)
To divide the expressions follow the steps
• Leave the first fraction
• Change division to multiplication
• Turn the second fraction upside down
We now have
×
![(2(2x+1))/((x-2)(x-2))](https://img.qammunity.org/2020/formulas/mathematics/high-school/xs72xnqsysggwec5un9qc4v3ws4ackwmak.png)
Final step is to cancel common factors from the numerators/denominators
=
← quotient