For what values of b, the equation x^2−ax+b=0 has a solution for any value of a? PLEASE I NEED IT SOON!

asked Oct 4, 2020 106k views

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2 votes

If you choose
b=0 the equation becomes

$x^2-ax = 0 \iff x(x-a) = 0$

which always has solutions
$x=0,\ x=a$

Stack answered Oct 6, 2020

by Stack

5.3k points

0 votes

I’m not sure about the wording of the question, but wouldn’t it be all real numbers?

Chris March answered Oct 8, 2020

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