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For what values of b, the equation x^2−ax+b=0 has a solution for any value of a? PLEASE I NEED IT SOON!
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For what values of b, the equation x^2−ax+b=0 has a solution for any value of a? PLEASE I NEED IT SOON!

User Artur Kucaj
by
5.2k points

2 Answers

2 votes

If you choose
b=0 the equation becomes


x^2-ax = 0 \iff x(x-a) = 0

which always has solutions
x=0,\ x=a


User Stack
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5.4k points
0 votes
I’m not sure about the wording of the question, but wouldn’t it be all real numbers?
User Chris March
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5.7k points
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