Question

Find the quotient................................

Answer 1

A.
`2a^3+3a^2-5a`

Explanation:

we are given

`(4a^4+6a^3-10a^2)`÷(2a)

so, we can divide 2a to all the terms

and we get

`((4a^4+6a^3-10a^2))/(2a) =(4a^4)/(2a)+(6a^3)/(2a)-(10a^2)/(2a)`

we can simplify it

`((4a^4+6a^3-10a^2))/(2a) =(2a* 2a^3)/(2a)+(2a* 3a^2)/(2a)-(2a* 5a)/(2a)`

`((4a^4+6a^3-10a^2))/(2a) =2a^3+3a^2-5a`

so, quotient is

`2a^3+3a^2-5a`

Answer 2

A

Explanation:

To find this quotient, we divide each term inside the parenthesis by
`2a`. Then we simplify. So we have:

`(4a^4)/(2a)+(6a^3)/(2a)-(10a^2)/(2a)\\=2a^(4-1)+3a^(3-1)-5a^(2-1)\\=2a^3+3a^2-5a`

Answer choice A is correct.