Question

A line contains points (4,2) and (0,-1). Wha is the equation of the line

Answer 1

the equation to find the slope is

`m = (y2 - y1)/(x2 - x1) \\ m = ( - 1 - 2)/(0 - 4) \\ m = ( - 3)/( - 4) \: or \: (3)/(4)`
now you have to use the point-slope formula

`y - y1 = m(x - x1) \\ y - ( - 1) = (3)/(4) (x - 0) \\ y + 1 = (3)/(4) x \\ y = (3)/(4) x - 1`
the equation of the line is

`y = (3)/(4) x - 1`