Question

Five times the sum of a number and 27 is greater than or equal to six times the sum of that number and 26. What's

the solution set of this problem?
0 (-2,-21)
0 (-2,-21
O [-21,42)
(21,42)

Answer 1

`x \leqslant - 21`

Explanation:

`5(x + 27) \geqslant 6(x + 26)`
`5x + 135 \geqslant 6x + 156`

`- 21 \geqslant x`

`x \leqslant - 21`