17.8k views
3 votes
PLEASE HELP!!

Let f(x)=8(3)^x^−2 +2 .

The graph of f(x) is stretched vertically by a factor of 3 to form the graph of g(x) .

What is the equation of g(x)?

Enter your answer in the box.

1 Answer

5 votes

Answer: The equation of g(x) is given by


g(x)=8(3^{x^(-2)+1}+2)

Explanation:

Since we have given that


f(x)=8(3)^x^(-2) +2

According to question, the graph of f(x) is stretched vertically by a factor of 3 to form the graph of g(x).

Equation for vertically stretch by a factor of 'a' is given by


g(x)=a* f(x)

Since there is vertically stretch by a factor of 3 i.e.


g(x)=3(8(3^{x^(-2)}))+2\\\\g(x)=8(3^{x^(-2)+1}+2)

Hence, the equation of g(x) is given by


g(x)=8(3^{x^(-2)+1}+2)

User MHouses
by
5.0k points