Answer:
C. Graph with asymptote at x =2, the portion of the graph to the left extends from y=1 to negative infinity crossing the x-axis at negative three. The portion to the right extends from infinity to the asymptote y=1.
Explanation:
We have the function
.
First we find the vertical asymptote. They are obtained by the zeros of the denominator.
i.e. x -2 = 0 → x = 2.
Therefore, the function has a vertical asymptote at x =2.
So, the options A) having asymptote at x = -3 and D) having asymptote at x = -2 are not correct.
Now, as the degree of both the polynomials in the numerator and denominator is same.
So, f(x) will not have a slant asymptote but there will exist a horizontal asymptote.
It can be obtained by dividing the leading terms.
i.e.
i.e y = 1.
So, the function has a horizontal asymptote at y = 1.
Now, according to the figure below, we can see that the graph on the left extends from y=1 to
crossing at x= -2.5 and the graph on the right extends from
to asymptote y=1.
Hence, the closest answer correct is option C.