Answer:
=
![z+(1)/(5)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/dhqlz2a5l5x1vurreukqrz38x397eaesdo.png)
Explanation:
AS we can see in the figure that a beam or a rod is balanced by a square on right side
while on the left side we have a smaller square and a triangle
Suppose the values written inside it are the weights of the shapes which are making it stable
So
Total on RHS = Total on LHS
Now Total on RHS = Value of bigger square
=
![(3)/(5)](https://img.qammunity.org/2020/formulas/mathematics/high-school/ham59d8d32yipgtxeagz7evpc6d3yqvvcb.png)
Total on LHS = Value of smaller sqaure + Value of triangle
=
![(1)/(5)+z](https://img.qammunity.org/2020/formulas/mathematics/middle-school/lnhk04ipmjs56p7nyhn2q3qxd79zbacsye.png)
Now we know to make this image a balanced one as shown n the figure
Total on RHS = Total on LHS
putting values gives us
=
![(1)/(5)+z](https://img.qammunity.org/2020/formulas/mathematics/middle-school/lnhk04ipmjs56p7nyhn2q3qxd79zbacsye.png)
which is the required equation