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Express the product of 4.0 × 10-2 m and 8.1 × 102 m using the correct number of significant digits. A. 3.2 × 101 B. 3.24 × 101 C. 32.4 D. 30

User Kasheena
by
8.7k points

2 Answers

4 votes

Step-by-step explanation:

The given digits whose product has to be calculated are
4.0 * 10^(-2)m and
8.1 * 10^(2)m.

The terms
10^(-2) and
10^(2) will be cancelled out. Therefore, product of
4.0 m * 8.1 m is
32.4 m^(2).

Hence, we can conclude that the correct number of significant digits for the product of
4.0 * 10^(-2)m and
8.1 * 10^(2)m is
32.4 m^(2).

User Marc Schmitt
by
8.8k points
2 votes

Answer:

The correct answer is option C.

Step-by-step explanation:

Significant figures : The figures in a number which express the value of the magnitude of a quantity to a specific degree of an accuracy is known as significant digits.


4.0* 10^(-2) m* 8.1* 10^2 m

Using identity =
a^m* a^n=a^(m+n)

=
4.0* 8.1* 10^(-2+2)


=32.4 m^2

There are three significant figures in the answer. Hence, correct answer is option C.

User Alex  Zezekalo
by
8.0k points

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