Question

In a bag of 60 candies, 36 are green and 45 have caramel in them. If the events of

picking a green candy and picking a candy with caramel are independent, what
percent of the green candies have caramel in them?

Answer 1

9/20

Explanation:

Total number of candies =60

Number of Green candies, n(G)=36

Number of candies with caramel, n(C)=45

Since the events are independent, the probability of selecting two candies where the first is green and the second has caramel is given by:

P(GC)=P(G) X P(C)

\begin{gathered}=\dfrac{n(G)}{n(S)} X \dfrac{n(C)}{n(S)} \\=\dfrac{36}{60} X \dfrac{45}{60}\\ =\dfrac{9}{20}\end{gathered}=n(S)n(G)Xn(S)n(C)=6036X6045=209

The probability in its lowest form is 9/20.