Question

Given sinθ=4/7 and θ lies in Quadrant II .

What is the exact value of cosθ in simplified form?

−4√33/33

−√33/4

√33/7

−√33/7

Answer 1

Answer:−√33/7

Explanation:

Second quadrant implies cos negative, as cos is projection from

unit circle to x axis.

sin^2+cos^2=1

cos= sqrt(1-sin^2)

sin^2 = 16/49

1-sin^2 = 33/49

sin= -sqrt(33)/7