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If a rectangle has perimeter of 70 a length of x and a width of x-9, find the value of the length of a rectangle

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Answer:

length = 22

width = 13

Explanation:

Perimeter of a rectangle is given by the formula

P =2(l+w)

we know the length is x

width is x-9

P =70

Substituting this into the equation

70 = 2(x+x-9)

Combining like terms

70=2(2x-9)

Distributing the 2

70 = 4x-18

Adding 18 to each side

70+18 = 4x-18+18

88 = 4x

Divide by 4

88/4 = 4x/4

22= x

we know the length is x

length = 22

width is x-9

width = 22-9= 13

User Radford Parker
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