18.6k views
2 votes
How do you expand (x-4)^2 ?

User Jeff Moden
by
8.2k points

2 Answers

4 votes

Answer:

(x - 4)^2 = x^2 - 8*x + 16

Explanation:

(a - b)^2 = a^2 - 2*a*b + b^2

(x - 4)^2 = x^2 - 2*x*4 + 4^2 = x^2 - 8*x + 16

User Omi Harjani
by
8.1k points
5 votes

Answer: x^2 - 8x + 16

Let y = x-4

(x-4)^2 = (x-4)*(x-4)

(x-4)^2 = y*(x-4) ... replace one copy of (x-4) with y

(x-4)^2 = x*y - 4*y .... distribute

(x-4)^2 = x*( y ) - 4( y )

(x-4)^2 = x(x - 4) - 4(x - 4) ... replace y with x-4

(x-4)^2 = x^2-4x-4x+16 .... distribute

(x-4)^2 = x^2 - 8x + 16

User Jay Supeda
by
7.4k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories