Answer : The volume of the gas is, 8.24018 L
Solution : Given,
Moles of gas = 2 moles
Pressure of gas = 1 atm
Temperature of gas = 50 K
Molar volume correction factor, b = 0.01709 L/mole
Gas constant, R = 0.08206 L atm/mole K
Formula used for real gas :
![(P+(an^2)/(V^2))(V-nb)=nRT](https://img.qammunity.org/2020/formulas/chemistry/high-school/u1n2zuyuaahgi1meq6tscta130tg5bg459.png)
where,
P = pressure of gas
V = volume of gas
T = temperature of gas
R= gas constant
n = number of moles of gas
b = molar volume correction factor
a = pressure correction factor
The value of 'a' is zero
Now put all the given values in this formula, we get the volume of gas.
![(P)(V-nb)=nRT](https://img.qammunity.org/2020/formulas/chemistry/high-school/f32h5xhr7a9kziru7auovyy4mpvamki2f8.png)
![V=(nRT)/(P)+nb](https://img.qammunity.org/2020/formulas/chemistry/high-school/1v7e4kaj6nxeidxam7k4wgv2ic4vdrd7j5.png)
![V=(2* 0.08206Latm/moleK* 50K)/(1atm)+(2* 0.01709L/mole)=8.24018L](https://img.qammunity.org/2020/formulas/chemistry/high-school/6sxvkcujsyfk07qqckhrlztvt0ubgmhggb.png)
Therefore, the volume of the gas is, 8.24018 L