Question

Divide the polynomial. (y /\3 - 4y /\ 2 + 7y - 6) (y - 2)

Answer 1

`\displaystyle\\(y^3 - 4y^2 + 7y - 6)/(y-2)=~~~~~\boxed{(-4y^2=-2y^2-2y^2)~~and~~(+7y=+4y+3y)}\\\\=(y^3 - 2y^2-2y^2 + 4y+3y - 6)/(y-2)=\\\\=(y^2(y - 2)-2y(y - 2)+3(y - 2))/(y-2)=\\\\=((y - 2)(y^2-2y+3))/(y-2)=y^2-2y+3`