Question

The vertices of square WXYZ have coordinates W(0,4), X(4,0), Y(0,-4) and Z(-4,0)

Answer 1

Are you asking which of these four are the answer to prove?

1.) PR≠QS, so PQRS is not a rectangle or a square. The slope of PR¯¯¯¯¯=1, and the slope of QS¯¯¯¯¯ =0, so PQRS is not a rhombus.

2.) PR=QS, so PQRS is a rectangle or a square. The slope of PR¯¯¯¯¯=1, and the slope of QS¯¯¯¯¯ =2, so PQRS is not a rhombus. PQ=QR=RS=SP=42–√, so PQRS is square.

3.) PR=QS, so PQRS is a rectangle or a square. The slope of PR¯¯¯¯¯=0, and the slope of QS¯¯¯¯¯ is undefined, so PR¯¯¯¯¯⊥QS¯¯¯¯¯. PQRS is a square.

4.) PR≠QS, so PQRS is not a rectangle or a square. The slope of PR¯¯¯¯¯=1, and the slope of QS¯¯¯¯¯ =2, so PQRS is not a rhombus.

Answer 2

So what's the question?