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The vertices of square WXYZ have coordinates W(0,4), X(4,0), Y(0,-4) and Z(-4,0)

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Answer:

Are you asking which of these four are the answer to prove?

1.) PR≠QS, so PQRS is not a rectangle or a square. The slope of PR¯¯¯¯¯=1, and the slope of QS¯¯¯¯¯ =0, so PQRS is not a rhombus.

2.) PR=QS, so PQRS is a rectangle or a square. The slope of PR¯¯¯¯¯=1, and the slope of QS¯¯¯¯¯ =2, so PQRS is not a rhombus. PQ=QR=RS=SP=42–√, so PQRS is square.

3.) PR=QS, so PQRS is a rectangle or a square. The slope of PR¯¯¯¯¯=0, and the slope of QS¯¯¯¯¯ is undefined, so PR¯¯¯¯¯⊥QS¯¯¯¯¯. PQRS is a square.

4.) PR≠QS, so PQRS is not a rectangle or a square. The slope of PR¯¯¯¯¯=1, and the slope of QS¯¯¯¯¯ =2, so PQRS is not a rhombus.

User Elon Zito
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So what's the question?
User Felix TheCat
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