7.9k views
0 votes
What is the area of a rectangle with a width of x2 + x + 1 and a length of
3x2 - 2x - 1?

User XMort
by
7.2k points

1 Answer

0 votes

Answer:


x^(4) + 3x³ - 3x - 1

Explanation:

The area (A) of a rectangle is calculated as

A = lw ( l is the length and w the width ) , thus

A = (3x² - 2x - 1)(x² + x + 1)

Each term in the second factor is multiplied by each term in the first factor, then

A = 3x²(x² + x + 1) - 2x(x² + x + 1) - 1(x² + x + 1) ← distribute parenthesis

= 3
x^(4) + 3x³ + 3x² - 2
x^(4) - 2x² - 2x - x² - x - 1 ← collect like terms

=
x^(4) + 3x³ - 3x - 1

User AfroThundr
by
8.1k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories