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The volume V in liters of air in the lungs during a five- second respiratory cycle is approximated by the model V= 0.1724t+0.1523t^2-0.0377t^3 where t is the time in seconds. Approximate the average volume of air in the lungs during one cycle. Round your answer to four decimal places.

User Pedromateo
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Answer:


\frac{\int\limits^5_0 {0.1724t+0.1523t^2-0.0377t^3} \, dt }{5-0} = 0.522

Explanation:

as with all functions f(t), the average value on [a,b] is


\frac{\int\limits^b_a {f(t)} \, dt }{b-a}

User Greg Bulmash
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