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Solve for x:abx²-(a⁴+b⁴)x+a³b³=0 ​
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Solve for x:abx²-(a⁴+b⁴)x+a³b³=0
​

User Mitch Goudy
by
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1 Answer

4 votes

Explanation:

abx² - (a⁴ + b⁴)x + (a³b³) = 0

(ax - b³)(bx - a³) = 0

Therefore x = b³/a or x = a³/b.

User Esco
by
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