Question

500 mL of He at 98 kPa expands to 750 mL.

Answer 1

500 mL of He at 98 kPa expands to 750 mL. Find P2.

P₂ = 65.3 kPa

Further explanation

Given

V₁=500 ml

P₁=98 kPa

V₂=750 ml

Required

P₂

Solution

Boyle's Law

At a constant temperature, the gas volume is inversely proportional to the pressure applied

`\rm p_1V_1=p_2.V_2\\\\(p_1)/(p_2)=(V_2)/(V_1)`

Input the value :

`\tt P_2=(P_1.V_1)/(V_2)\\\\P_1=(98.500)/(750)\\\\P_2=65.3~kPa`