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Solve the Solve the simultaneous equations 2x+3y=20 x+5y=31

User Remy Wang
by
8.9k points

1 Answer

5 votes

Answer:


x = 1 and
y = 6

Explanation:

Given


2x + 3y = 20


x + 5y = 31

Required

Solve for x and y

Make x the subject in the second equation


x = 31 - 5y

Substitute 31 - 5y for x in
2x + 3y = 20


2(31 - 5y) + 3y = 20


62 - 10y + 3y = 20


62 - 7y = 20

Collect like terms


-7y = 20 - 62


-7y = - 42

Solve for y


y = (-42)/(-7)


y = 6

Substitute 6 for y in
x = 31 - 5y


x = 31 - 5 * 6


x = 31 - 30


x = 1

User Dan Tang
by
7.2k points

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