Answer:
N165.53°E
Explanation:
Given the following vector points
Vx = -43.0units
Vy = 11.1 units
The direction of the vector is expressed using the formula:
θ = tan^-1(Vy/Vx)
θ = tan^-1(11.1/-43.0)
θ = tan^-1(0.2581)
θ = -14.47°
Since tan is negative in the second quadrant, hence the required direction will be θ = 180-14.47
θ = 165.53°
Hence the direction is N165.53°E