Question

a student determines the circumference of a golf ball. a man pulls a sledge of mass 25 kg across level ground with a horizontal force of 60 N. a constant force of friction of 20 N acts on sledge. what is the acceleration of the sledge?​

Answer 1

Calculate resultant force:

R = ma

Descomposing:

F - Fr = ma

Replacing we have:

60 N - 20 N = 25 kg * a

Resolving:

40 N = 25 kg * a

40 N / 25 kg = a

1,6 m/s^2 = a

The aceleration is 1,6 meters per second squared.

Answer 2

Step-by-step explanation:

Fnet = Ft - Ff = 60N - 20N = 40N

a = Fnet / m = 40N / 25kg = 1.6m/s².