Answer:
![V_(rms)=6\sqrt2\ V](https://img.qammunity.org/2021/formulas/engineering/college/g5w3vbtwcndukkoseunjk93v6vts2mplg8.png)
Step-by-step explanation:
Given that,
The maximum voltage of an alternating current,
![V_(max)=12\ V](https://img.qammunity.org/2021/formulas/engineering/college/yd10gibtpdghpggbgnilix4t0now1tnr9k.png)
We need to find the highest Vrms that can be supplied to this component while staying below the voltage limit.
Let rms voltage in terms of peak voltage is given by :
![V_(rms)=(V)/(\sqrt2)\\\\=(12)/(\sqrt2)\\\\=(12)/(\sqrt2)* (\sqrt2)/(\sqrt2)\\\\=(12\sqrt2)/(2)\\\\=6\sqrt2\ V](https://img.qammunity.org/2021/formulas/engineering/college/cpscqbdovvdhyw69bfqlz6hbsuxbi1gd66.png)
Hence, the required rms voltage is
.