Question

0=(2y−1)(8−y) Let y=u, y=d. What is the value of u×d

Answer 1

The value of uxd=4

Explanation:

since y=u, y=d, y=y

y=1/2 and 8

2y-1=0

2y=1

y=1/2

8-y=0

8=y

1/2*8=4

Answer 2

4

Explanation:

0=(2y−1)(8−y)

Using the zero product property

2y-1 =0 8-y =0

2y =1 8=y

y =1/2 y= 8

Let y=u, y=d

u = 1/2 d = 8

We want the value of u*d

u*d = 1/2 *8 = 4