Question

The number of peanuts in bags is normally distributed with a mean of 172.5 peanuts and a standard deviation of 1.9 peanuts. What is the z-score of a bag containing 168 peanuts

Answer 1

- 2.368

Explanation:

Given that :

Mean (m) = 172. 5

Standard deviation (s) = 1.9

Score (x) = 168

The Zscore can be obtained thus :

Zscore = (x - m) / s

Zscore = (168 - 172.5) / 1.9

Zscore = - 4.5 / 1.9

Zscore = −2.368421

Zscore = - 2.368