Question

Determine the change in energy when an electron transitions from n= to n=5?

Answer 1

ΔE = 13.056 ev

Explanation:

Energy associated with nth state is,

En = -13.6/n²

For n = 1

E₁ = -13.6 / 1²

E₁ = -13.6/1

E₁ = -13.6 ev

Kinetic energy of electron = -E₁ = 13.6 ev

For n = 5

E₅ = -13.6 / 5²

E₅ = -13.6/25

E₅ = -0.544 ev

Kinetic energy of electron = -E₅ = 0.544 ev

Wavelength of radiation emitted:

ΔE = hc/λ = E₅ - E₁

by putting values,

ΔE = -0.544ev - (-13.6 ev )

ΔE = 13.056 ev