Question

Find the equation of the line that is parallel to the given line and passes through the given point.

y=-6x + 9; (8,9)
The equation is y =

Answer 1

y=-6x+9

0=-6x+9

6x=9

x=9/3

x=3/2

Answer 2

y = -6x - 39

Explanation:

A parallel line will have the same slope so m= -6, but it will have different points.

So we have y= -6x + b and the points are (8,9)

Substitute that in

9 = -6*-8 + b

9 = 48 + b

subtract 48 on both sides

9-48 = 48 - 48 + b

-39 = b

so equation is

y = -6x -39

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