Question

A

AMINO BORCY
Two forces of 80 N and 70 N act simultaneously at a point Find the resultant force. if the
Angle between them is 150 dgree

Answer 1

`F_r = 40.01N`

Step-by-step explanation:

Given

Let the two forces be
`F_1\ and\ F_2`

`F_1 = 80N`

`F_2 = 70N`

`\theta = 150\deg`

Required

Determine the resultant force
`F_r`

This will be solved using parallelogram law of resultant force.

The equation is:

`F_r^2 = F_1^2 + F_2^2 + 2F_1F_2cos\theta`

Substitute values for
`F_1`,
`F_2` and
`\theta`

`F_r^2 = 80^2 + 70^2+ 2 * 70 * 80 * cos\ 150`

`F_r^2 = 6400 + 4900 + 11200* cos\ 150`

`F_r^2 = 6400 + 4900 + 11200* -0.8660`

`F_r^2 = 6400 + 4900 - 9699.2`

`F_r^2 = 1600.8`

Take the square root of both sides

`F_r = \sqrt{1600.8`

`F_r = 40.01N`

Hence, the resultant force is 40.01 N