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A

AMINO BORCY
Two forces of 80 N and 70 N act simultaneously at a point Find the resultant force. if the
Angle between them is 150 dgree

User Lulceltech
by
6.8k points

1 Answer

6 votes

Answer:


F_r = 40.01N

Step-by-step explanation:

Given

Let the two forces be
F_1\ and\ F_2


F_1 = 80N


F_2 = 70N


\theta = 150\deg

Required

Determine the resultant force
F_r

This will be solved using parallelogram law of resultant force.

The equation is:


F_r^2 = F_1^2 + F_2^2 + 2F_1F_2cos\theta

Substitute values for
F_1,
F_2 and
\theta


F_r^2 = 80^2 + 70^2+ 2 * 70 * 80 * cos\ 150


F_r^2 = 6400 + 4900 + 11200* cos\ 150


F_r^2 = 6400 + 4900 + 11200* -0.8660


F_r^2 = 6400 + 4900 - 9699.2


F_r^2 = 1600.8

Take the square root of both sides


F_r = \sqrt{1600.8


F_r = 40.01N

Hence, the resultant force is 40.01 N

User Germankiwi
by
8.1k points

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