Question

Guys help I am stuck on this question I have to send my winter holiday

48 girls and 64 boys belong to the Twelve Mile Coulee School choir. The choir teacher plans to arrange the students into equal rows (the same number of students in each row). Only girls or boys will be in each row. What is the greatest number of students that could be in each row?

Answer 1

Explanation:

I believe for this question you need to find the HCF (or GCF you may say) of 48 and 64

HCF - Highest Common Factor

GCF - Greatest common Factor

First, prime factorize 48 and 64 (write them in the product of their prime numbers)

64 = 2 × 2 × 2 × 2 × 2 × 2

48 = 2 × 2 × 2 × 2 × 3

Choose common prime factors (all of them that are common)

on observation, there is 2 × 2 × 2 × 2 common between both of them

which is 16.

So 16 maximum people in each row

Also additional thing, it's fine if some questions were wrong, try and attempt it yourself first before asking it from someone. Getting used to ask someone is going to be troublesome in the long run. If you get stuck, then get help from your teachers (unless the teacher is unco-operative) in which case, seek help from your friends, or talk to your parents about it if you freely share stuff with them.

But anyway, hope that helps ^

Answer 2

16

Explanation:

To find the greatest number of students that could be in each row, we need to find their greatest common factor. We can list out their prime factors first.

48: 2 × 2 × 2 × 2 × 3

64: 2 × 2 × 2 × 2 × 2 × 2

Here, their common prime factors are 2 × 2 × 2 × 2 which is 16. Thus, the greatest number of students that could be in each row is 16.

No. of rows in the girls = 48 ÷ 16

= 3

No. of rows in the boys = 64 ÷ 16

= 4