9514 1404 393
Answer:
0.40 W/(m·K)
Explanation:
Units of thermal conductivity are ...
W/(m·K)
The length dimension in the denominator comes from the ratio of area to thickness. That is, we can compute the thermal conductivity from ...
(62 W)(0.163m)/(1.1 m²·23K) ≈ 0.40 W/(m·K)