Question

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A car slows down from -27.7m/s to -10.9m/s while undergoing a displacment of -105m. What was its acceleration?

Answer 1

Given :

A car slows down from -27.7 m/s to -10.9 m/s while undergoing a displacement of -105 m.

To Find :

The acceleration of the car.

Solution :

We know, by equation of motion :

`2as = v^2 -u^2\\\\a = (v^2 -u^2 )/(2s)\\\\a = ((-10.9)^2 - ( -27.7)^2)/(2* ( -105 ))\\\\a = 3.088\ m/s^2`

Therefore, acceleration of the car is 3.088 m/s².