Question

Which of the following is a solution to the equation x
`x^(2)`– 6x + 5 = 0?

Answer 1

`\huge\boxed{\sf x =5 \ \ \ OR \ \ \ x = 1}`

Explanation:

Given equation:

`x^2-6x+5=0`

Using mid-term break formula

• Multiply -5 and -1 gives +5 (side term) and adding them gives -6 (mid term).
• So, split -6 into -5 and -1

`x^2-5x-x+5=0\\\\Take \ common\\\\x(x-5)-1(x-5)=0\\\\Take \ (x-5) \ common\\\\(x-5)(x-1)=0`

Either,

x - 5 = 0 OR x - 1 = 0

x = 5 OR x = 1

`\rule[225]{225}{2}`