Answer:
![\huge\boxed{\sf Current = 6\ Ampere}](https://img.qammunity.org/2023/formulas/physics/high-school/9yfnhrkmecjn4gam4z9z3uj36e475ds8a0.png)
Step-by-step explanation:
In a parallel circuit, Total resistance is:
![\displaystyle (1)/(R_T) =(1)/(R_1) +(1)/(R_2)](https://img.qammunity.org/2023/formulas/physics/high-school/zvf8d65kuzuef25ad6kkr27ujxs0gkersf.png)
Where
= 6Ω and
= 12Ω
Finding
:
![\displaystyle (1)/(R_T) =(1)/(6) +(1)/(12) \\\\(1)/(R_T) =(1 * 2+1)/(12) \\\\(1)/(R_T) =(3)/(12) \\\\(R_T)/(1) = (12)/(3) \\\\\boxed{R_T=4 \ Ohm}](https://img.qammunity.org/2023/formulas/physics/high-school/c9mnbz9pay7c21mi9d2jtl6l6xqwc3s3ph.png)
Finding current:
We know that:
V = IR (Ohm's Law)
V = 24 V, R = 4 Ω (V given, R found)
24 = I(4)
Divide 4 to both sides
6 A = I
Current = 6 Ampere
![\rule[225]{225}{2}](https://img.qammunity.org/2023/formulas/english/college/eq413d752mwtrwwenrzwldxt4w1olmf1b3.png)