Answer:
The length of the pendulum is 2.954 m.
Step-by-step explanation:
Given;
period of the pendulum, T = 3.45 s
The period of the pendulum oscillation is given as;
![T = 2\pi \sqrt{(l)/(g) } \\\\(T)/(2\pi) = \sqrt{(l)/(g) }\\\\(T^2)/(4\pi ^2) = (l)/(g) \\\\l = (gT^2)/(4\pi ^2) \\\\](https://img.qammunity.org/2021/formulas/physics/high-school/5ykbuqc7cc46ixjqav941s6xu4bg4x40ff.png)
where;
L is length of the pendulum
g is acceleration due to gravity on Earth = 9.8 m/s²
![l = (gT^2)/(4\pi ^2)\\\\l = ((9.8)(3.45)^2)/(4\pi ^2)\\\\l = 2.954 \ m](https://img.qammunity.org/2021/formulas/physics/high-school/qmp9a7sp9pogi0jy0lmixrhymqb7iuu0pd.png)
Therefore, the length of the pendulum is 2.954 m.