Question

What volume of H2so4 Solution Cspecific gravity=-1.28 and strength =24.7% by mass) will be required to react completely with 125g ZnC032?

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Answer 1

The volume = 309.04 ml

Further explanation

Given

Specific gravity=-1.28 and strength =24.7% by mass of H₂SO₄

mass 125g of ZnC0₃

Required

The volume of H₂SO₄ Solution

Solution

Reaction

ZnCO₃ + H₂SO₄ → ZnSO₄ + CO₂ + H₂O

mol of ZnCO₃(MW=125.4 g/mol) :

`\tt mol=(125)/(125.4)=0.997`

From equation, mol ZnCO₃ : H₂SO₄= 1 : 1 so mol H₂SO₄=0.997

mass of H₂SO₄ (MW=98 g/mol) :

`\tt mass=mol* MW=0.997* 98=97.706~g`

mass of solution :

`\tt (100)/(24.7)* 97.706=395.57~g`

Volume of solution :(density of solution=1.28 g/ml for the reference substance is water(density=1 g/ml)

`\tt V=(395.57)/(1.28)=309.04~ml`