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At fast food restaurant, 90% of the customers’ order hamburger. If 72% of the customer’s order hamburger and French fries, what is the probability that a customer who orders hamburger will also order French fries?

User Thesonix
by
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1 Answer

4 votes

Answer:

0.8

Explanation:

A = hamburger

B = french fries

P(B|A)

P(AB)/P(A)

= 0.72/0.9

= 0.8

User Cistearns
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5.0k points