Answer:
(0.9036, 0.9064)
Explanation:
Given that:
True mean (m) = 0.9050
Standard deviation (s) = 0.0100
Sample size ( n) = 48
Interval for 90% of the sample mean :
Mean ± Error
Error = Zcritical * (standard deviation /sqrt(n))
Zcritical at 90% confidence interval = 1.64
Hence,
Error = 1.64 * (0.0100/sqrt(48)) = 0.0014433
Lower boundary = m - Error = (0.9050 - 0.0014433) = 0.9035567
Upper boundary = m + Error = (0.9050 + 0.0014433) = 0.9064433
(0.9036, 0.9064)