The mass of sodium hydrogen carbonate : 10.5 g
Further explanation
Given
1.5 dm' of CO₂
1 mol gas= 24 L at RTP(25 °C, 1 atm)
Required
the mass of sodium hydrogen carbonate
Solution
Decomposition reaction of Sodium hydrogen carbonate :
2 NaHCO₃ (s) ⇒ Na₂ CO₃ (s) + H₂ O(g) + CO₂ (g)
mol CO₂ :
![\tt mol=(1.5)/(24)=0.0625](https://img.qammunity.org/2021/formulas/chemistry/college/ep6kvt21t8678g4n112lyfcmk6y33f2b11.png)
From the equation, mol ratio of NaHCO₃ : CO₂ (g) = 2 : 1, so mol NaHCO₃ :
![\tt 2* 0.0625=0.125](https://img.qammunity.org/2021/formulas/chemistry/college/o2401jyd87os7v9li9mth6n15x26ywn1b2.png)
Mass NaHCO₃(MW=23+1+12+3.16=84 g/mol) :
![\tt mass=mol* MW\\\\mass=0.125* 84\\\\mass=10.5](https://img.qammunity.org/2021/formulas/chemistry/college/3q5swlaflqwkfp47jsm8urbw9be77arqir.png)