Question

A 43 kg box is being pushed and pulled by

three forces. The first force is 155 N to the
right. The second force is 227 N to the left.
The third force is 113 N to the right. What is
the acceleration of the box?

Answer 1

a = - 0.209 [m/s²]

Step-by-step explanation:

To solve this problem we must use Newton's second law which tells us that the sum of forces on a body is equal to the product of mass by acceleration.

∑F = m*a

We will take the positive forces to the right and the negative forces to the left.

`155-277+113=43*a\\-9=43*a\\a = - 0.209[m/s^(2) ]`

The negative sign means that the box accelerates in a negative direction to the left.