Find four consecutive negative integers whose sum is -42

Question

asked Dec 15, 2021 165k views

2 Answers

Michael Thompson · Answer 1 · 2021-12-19T09:02:07+0000

Answer:

-12, -11, -10 and -9 add up to -42

Explanation:

We can solve this by expressing all four of those integers relative to the first one:

$x + (x + 1) + (x + 2) + (x + 3) = -42\\4x + 6 = -42\\4x = -48\\x = -12$

so we know that the lowest one is -12, and the other three are sequentially higher value:

-12, -11, -10 and -9