Write an equation in slope-intercept form of the line that passes through the given point and is perpendicular to the graph of the given equation. (5,0); y+1=2(x-3)

Question

asked Oct 5, 2021 211k views

1 Answer

GJK · Answer 1 · 2021-10-11T10:20:24+0000

Answer:

y=(-1)/(2)x +(5)/(2)

Explanation:

Slope intercept form looks like y=mx+b

The slope (m) needs to be the opposite reciprocal of 2, because the line needs to be perpendicular the given line. Therefore, m = -1/2

We can write the equation in point-slope form first because we're given a point and now we have the slope. The equation would be
y-0=(-1)/(2) (x-5)

Rewriting, we get
y=(-1)/(2)x +(5)/(2)